<h3>
<u>Explanation</u></h3>
- Given the system of equations.
- Substitute y = -4x in the second equation.
- Substitute the value of x in any given equations. I will substitute the value of x in the first equation.
- Answer Check by substituting both values in two equations.
<u>First</u><u> </u><u>Equation</u>
<u>Second</u><u> </u><u>Equation</u>
Both equations are true for the value of x and value of y.
<h3>
<u>Answer</u></h3>
<u>
</u>
<u>Coordinate</u><u> </u><u>Point</u><u> </u><u>form</u>
<u>
</u>
Ok so assume that if you have
xy=0 then x and y=0
-1/4(x^2-4x+3)>0
multiply both sides by -4 to clear fraction (-4/-4=1)
flip sign
x^2-4x+3<0
factor
(x-3)(x-1)<0
we know that (+) times (-)=(-) and
(-) times (-)=(+) so we don't want them to be both negative, we want different sign
we cannnot have 3 since it would be (0)(2)<0 which is false
we cannot have 1 either since (-2)(0)<0 is also false
lets see if the solution is in betwen 3 and 1 or outside of 3 and 1
ltry 2
2^3-4(2)+3<0
8-8+3<0
3<0
false
therefor it is outside ie
x>3 and x<1
18.95x0.75=14.2125
18.95-14.2125=4.73
You will pay $4.73
Answer: Kite
Step-by-step explanation:
