Answer:
Step-by-step explanation:
Woah thats hard what year you in?
15,785 and well try to do your best haha
When roots of polynomials occur in radical form, they occur as two conjugates.
That is,
The conjugate of (a + √b) is (a - √b) and vice versa.
To show that the given conjugates come from a polynomial, we should create the polynomial from the given factors.
The first factor is x - (a + √b).
The second factor is x - (a - √b).
The polynomial is
f(x) = [x - (a + √b)]*[x - (a - √b)]
= x² - x(a - √b) - x(a + √b) + (a + √b)(a - √b)
= x² - 2ax + x√b - x√b + a² - b
= x² - 2ax + a² - b
This is a quadratic polynomial, as expected.
If you solve the quadratic equation x² - 2ax + a² - b = 0 with the quadratic formula, it should yield the pair of conjugate radical roots.
x = (1/2) [ 2a +/- √(4a² - 4(a² - b)]
= a +/- (1/2)*√(4b)
= a +/- √b
x = a + √b, or x = a - √b, as expected.
Which questions can you please send a link? :)
Answer:
Shortest Leg: 5 inches, Hypotenuse: 13 inches
Step-by-step explanation:
A right triangle follows the pythagorean theorem, a^2+b^2=c^2. C is the hypotenus. A combination found using this is 5, 12, and 13. To double check this, we know that the hypotenus is 2x+3, where x is the smallest leg.
