Since liquid CO2 cannot exist at pressures lower than 5.11 atm, the triple point is defined as 56.6 °C and 5.11 atm.
Are CO2 liquids explosive?
Although it can impair judgement at high doses, carbon dioxide is neither poisonous nor combustible. Asphyxiation is typically seen as the primary risk associated with CO2. The Boiling Liquid Expanding Vapour Explosion, however, is a serious risk connected to compressed CO2 (BLEVE)
What PSI does CO2 turn into liquid at?
Only at pressures more than 5.1 atm does liquid carbon dioxide form; the triple point of carbon dioxide is approximately 518 kPa at 56.6 °C. Depending on the pressure, the liquid's boiling point ranges from -70°F to +88°F. The expansion ratio when vaporised at 60°F is 535:1. CO2 is a gas or liquid.
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Answer:
The Kc of this reaction is 311.97
Explanation:
Step 1: Data given
Kp = 0.174
Temperature = 243 °C
Step 2: The balanced equation
N2(g) + 3H2(g) ⇌ 2NH3(g)
Step 3: Calculate Kc
Kp = Kc *(RT)^Δn
⇒ with Kp = 0.174
⇒ with Kc = TO BE DETERMINED
⇒ with R = the gas constant = 0.08206 Latm/Kmol
⇒ with T = the temperature = 243 °C = 516 K
⇒ with Δn = number of moles products - moles reactants 2 – (1 + 3) = -2
0.174 = Kc (0.08206*516)^-2
Kc = 311.97
The Kc of this reaction is 311.97
Answer:
0.46 V
Explanation:
The emf for the cell is given by:
Eº cell = Eº oxidation + Eº reduction
From the given balanced chemical equation, we can deduce that Fe²⁺ has been oxidized to Fe³⁺, and O reduced from 0 to negative 2, according to the half cell reactions:
4Fe²⁺ ⇒ Fe³⁺ + 4e⁻ oxidation
O₂ + 4H⁺ + 4 e⁻ ⇒ 2 H₂O reduction
From reference tables for the standard reduction potential, we get
Eº red Fe³⁺ / Fe²⁺ Eºred = 0.77 V
Eº red O₂ / H₂O Eºred = 1.23 V
Now all we need to do is change the sign of Eº reduction for the species being oxidized ( Fe²⁺ ) and add it to Eº reduction O₂:
Eº cell = Eº oxidation + Eº reduction = - (0.77 V ) + 1.23 V = 0.46 V
Answer:
The molarity of the solution is 1.1
Explanation:
Molarity is a measure of the concentration of that substance that is defined as the number of moles of solute divided by the volume of the solution.
The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:
Molarity is expressed in units
In this case
- number of moles of solute= 0.564 moles
- volume= 0.510 L
Replacing:
Solving:
molarity= 1.1
<u><em>The molarity of the solution is 1.1 </em></u><u><em></em></u>