Answer:
93.125 × 10^(19)
Explanation:
We are told the asteroid has acquired a net negative charge of 149 C.
Thus;
Q = -149 C
charge on electron has a value of:
e = -1.6 × 10^(-19) C
Now, for us to determine the excess electrons on the asteroid, we will just divide the net charge in excess on the asteroid by the charge of a single electron.
Thus;
n = Q/e
n = -149/(-1.6 × 10^(-19))
n = 93.125 × 10^(19)
Thus, it has 93.125 × 10^(19) more electrons than protons
Answer:
Density = 1.1839 kg/m³
Mass = 227.3088 kg
Specific Gravity = 0.00118746 kg/m³
Explanation:
Room dimensions are 4 m, 6 m & 8 m. Thus, volume = 4 × 6 × 8 = 192 m³
Now, from tables, density of air at 25°C is 1.1839 kg/m³
Now formula for density is;
ρ = mass(m)/volume(v)
Plugging in the relevant values to give;
1.1839 = m/192
m = 227.3088 kg
Formula for specific gravity of air is;
S.G_air = density of air/density of water
From tables, density of water at 25°C is 997 kg/m³
S.G_air = 1.1839/997 = 0.00118746 kg/m³
In simple words, smoothing can be defined as the circuit which is done to eliminate the ripple from the yield of a direct current power supply.
<u>Explanation:</u>
<u>Necessity of smoothing:</u>
- Smoothing can be also applied in the form of a capacitor that acts to decrease or level out variations in a signal. And these capacitors are mostly used after power supply in voltage.
- The yield DC voltage of a half-wave rectifier provided in the figure of a sinusoidal wave.
- In a method to provide a constant DC voltage from a corrected AC source, a filter or smoothing circuit is required.
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Answer:(A-P,S;B-P,S;C-Q,S;D-P,S)
Solution
(A)→P,S,(B)→P,S,(C)→Q,S,(D)→P,S.
Explanation:
