Answer: 0, 1, -3
Step-by-step explanation:
f(x) = x^3 +2x^2 -3x
f(x) = x(x^2 +2x-3)
f(x) = x(x-1)(x+3)
to find zeroes, plug into f(x) and solve for each value of x. doing this gives 0, 1, and -3
I would say D, determine if it can be factored by grouping (sorry, I forgot to put in the answer here).
The equation given in the question is
3(3x - 1) + 2(3 - x) = 0
9x - 3 + 6 - 3x = 0
6x + 3 = 0
6x = - 3
x = - (3/6)
= - (1/2)
So the value of x as has been determined above is -1/2. I hope the procedure is clear enough for you to understand.<span>You can
always use this method for solving problems that are similar in type without
requiring any help from outside. </span>