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2 years ago

Which points are the vertices of the ellipse?

Mathematics

2 answers:

Phoenix [80]2 years ago

6 0

Points m and n
Are the answer

Firdavs [7]2 years ago

3 0

Answer:

Your answer is A) points G and H

Step-by-step explanation:

I took the test on edge 100%

You might be interested in

Explain how you can tell if the expressions 7x – 4 and 6x – 4 – x are equivalent.

Alina [70]

Hey there!

Combine Like Terms and see if the expressions are equivalent or not.

6x-4-x

6x-x-4

5x-4

Is 5x-4 equivalent to 7x-4? No.

Hope everything is clear.

Let me know if you have any questions!

Always remember: Knowledge is power!

8 0

1 year ago

AN SOMEONE PLEASE HELP ME SOLVE THIS!!

stepan [7]

A) Scale factor:

Divide 2 congruent sides:

24 / 36 = 0.667

From PQR to XYZ is a 0.667 (2/3 as a fraction) scale factor.

B) Volume = (1/2 x base x side) x height:

Volume = 1/2 * 36 x 48 = 864 * 15 = 12,960 cubic inches.

C) Find the height of the prism:

7776 = (1/2 * base * sides) x height

7776 = (1/2 x 36 x 48) * height

7776 = 864 * height

Height = 7776 / 864 = 9 inches.

The scale factor is 2/3, the height of XYZ = 2/3 *9 = 6 inches.

Volume of XYZ = 1/2 x 24 x 32 = 384 x 6 = 2,304 cubic inches.

3 0

2 years ago

Find the average value of f(x+y)=sin(x+y) over

Troyanec [42]

For each given region $D$ , the average value of $f$ over $D$ is the integral of $f$ over $D$ divided by the area of $D$ . In both cases, $D$ is a rectangle so the area is trivial.

a. The area of $D$ is $\dfrac\pi3\cdot\dfrac{5\pi}3=\dfrac{5\pi^2}9$ . The integral of $f$ over $D$ is

$\displaystyle\int_0^{5\pi/3}\int_0^{\pi/3}\sin(x+y)\,\mathrm dx\,\mathrm dy$

$\displaystyle=\int_0^{5\pi/3}\left(\cos y-\cos\left(y+\dfrac\pi3\right)\right)\,\mathrm dy$

$=\sin\dfrac{5\pi}3-\sin\left(\dfrac{5\pi}3+\dfrac\pi3\right) - \sin0+\sin\dfrac\pi3=0$

So the average value of $f$ over this region is 0.

b. The area of $D$ is $\dfrac{2\pi}3\cdot\dfrac{7\pi}6=\dfrac{7\pi^2}9$ . The integral of $f$ is

$\displaystyle\int_0^{7\pi/6}\int_0^{2\pi/3}\sin(x+y)\,\mathrm dx\,\mathrm dy$

$=\displaystyle\int_0^{7\pi/6}\left(\cos y-\cos\left(y+\frac{2\pi}3\right)\right)\,\mathrm dy$

$=\sin\dfrac{7\pi}6-\sin\left(\dfrac{7\pi}6+\dfrac{2\pi}3\right) - \sin0+\sin\dfrac{2\pi}3=\dfrac{\sqrt3}2$

The average vale of $f$ over this region is then $\dfrac{\frac{\sqrt3}2}{\frac{7\pi^2}9}=\dfrac{9\sqrt3}{14\pi^2}$ .

4 0

2 years ago

68. Solve: 46x - 10) = 8x + 40<br>A 0<br>B.5/2<br>ina<br>c. 23<br>D. 5

Artist 52 [7]

Solve: 4(6x - 10) = 8x + 40

A 0

B.5/2

c. 23

D. 5

<h3><u>Answer:</u></h3>

Option D

The solution to given equation is x = 5

<h3><u>Solution:</u></h3>

Given that we have to solve the given equation

4(6x - 10) = 8x + 40

Let us solve the above expression and find value of "x"

Multiplying 4 with terms inside bracket in L.H.S we get,

24x - 40 = 8x + 40

Move the variables to one side and constant terms to other side

24x - 8x = 40 + 40

Combine the like terms,

16x = 80

$x = \frac{80}{16} = 5$

Thus solution to given equation is x = 5

3 0

2 years ago

How many times does 40 go into 280

igor_vitrenko [27]

40 goes into 280 7 times to figure this out just simply divide 280/40

3 0

2 years ago

Read 2 more answers