3u^2+3usa-6usa-6s^2a^2
3u^2-3usa-6s^2a^2
Please, use " ^ " to denote exponentiation: p(t) = t^2 + 5t + 6.
To find the critical points, differentiate p(t) with respect to t, set the result = to 0, and then solve the resulting equation for t:
p '(t) = 2t + 5 = 0
Solving for t: 2t = -5, and so t = -5/2. (-5/2, p(-5/2)) is the critical point. That evaluates to (-5/2, -0.25). This happens to be the vertex of a parabola that opens up.
There all log base 3, the base won't matter as long as they're all the same.
log(x^2/y)=2log(x)-log(y)=2(4.5)-3=6
Answer: c. 6
Answer:
3 to 7
Step-by-step explanation:
Answer:
Original number = 38
Step-by-step explanation:
10*x + y
x = y - 5
10y + x = 2 (10x + y) + 7
10y + y - 5 = 2(10(y - 5) + y) + 7
11y - 5 = 2(10y - 50 + y ) + 7
11y - 5 = 2(11y - 50) + 7
11y - 5 = 22y - 100 + 7
11y - 5 = 22y - 93
11y + 88 = 22y
88 = 11y
y = 8
x = y - 5
x = 8 - 5
x = 3
So the original number is 38. Does that work?
3 is 5 less than 8.
83 = 2*38 + 7
83 = 76 + 7
83 = 83. Yes it works.
