For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
Answer:
<h2>-1</h2>
Step-by-step explanation:
2 - (-4) + (-y)
Substitute y = 7 to the expression:
2 - (-4) + (-7) = 2 + 4 - 7 = 6 - 7 = -1
Answer:
1.)
132 cm - 11 cm = 121 cm
So let the hypotenuse be x and the other leg be (121 - x).
11^2 + (121 - x)^2 = x^2
121 + 121^2 - 121(2)x = 0
x = 1/2 + 121/2 = 61 cm
Step-by-step explanation: not sure if this is right or not
The answer would be 93 cents divide it by 2 since you want to share with someone and you would have 46 cents and a nickel for both people
