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2 years ago

2x-1/4 + x/3 = 2 Solve the equation

Mathematics

1 answer:

Marta_Voda [28]2 years ago

7 0

Answer:

below

Step-by-step explanation:

steps are shown above

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Find the value of x. 3x(5+2)=16

Iteru [2.4K]

Answer:

16/21

Step-by-step explanation:

We are given the equation 3x(5 + 2) = 16.

By order of operations, let's add the two numbers in the parentheses first:

3x(5 + 2) = 16

3x(7) = 16

Now, we must multiply 3x by 7:

3x * 7 = 16

21x = 16

Divide both sides by 21:

x = 16/21

The answer is thus 16/21.

~ an aesthetics lover

8 0

2 years ago

Read 2 more answers

How would one solve this

yaroslaw [1]

Sorry i really need points

4 0

2 years ago

which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

6 0

2 years ago

What is the equation of the trend line? Enter your answers in the boxes. K = _J +_

MrRissso [65]

The y-intercept of the trend line is (0,28). The slope of this line is
28-0
m = --------- = 2
14-0

Thus, the equation of the trend line, in variables K and J, is

K = 2J + 28

8 0

2 years ago

The function h(x) is given below.

Nutka1998 [239]

Answer:

Step-by-step explanation:

I wish I knew :(

8 0

2 years ago