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2 years ago

9

(HELP ASAP) A bag contains lettered tiles. The theoretical probability of choosing a vowel is 30%. The bag contains 42 consonant

s. How many tiles are in the bag?

2 answers:

luda_lava [24]2 years ago

4 0

Answer: I'm not so sure but my answer is 54 or 55

Step-by-step explanation:

The probability of choosing a vowel is 30%, and there are 42 consonants, so we would set up an equation like this:

42 times 30% (0.30) = 12.6 (rounded to 12)

So we have 12 vowel and 42 consonants in the bag, the total tiles would be:

12+42= 54

* But in case your teacher rounded up to 13 (vowels), the answer should be 55. But the probability rounded up to 13 is very low.

AveGali [126]2 years ago

3 0

55 your welcome pretty sure that’s it

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2 years ago

Read 2 more answers

What are the solutions to the following system?

bija089 [108]

The solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Solution:

Given equation:

$-2 x^{2}+y=-5$

Add $2 x^{2}$ on both sides.

$-2 x^{2}+y+2 x^{2}=-5+2 x^{2}$

$y=-5+2 x^{2}$ -------- (1)

$y=-3 x^{2}+5$ (given) -------- (2)

Equate (1) and (2).

$-5+2 x^{2}=-3 x^{2}+5$

Add $3 x^{2}$ on both sides.

$-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}$

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Add 5 on both sides.

$-5+5x^{2}+5=5+5$

$5x^{2}=10$

Divide by 5 on both sides, we get

$x^{2}=2$

Taking square root on both sides, we get

$x=\sqrt{2}, x=-\sqrt{2}$

Substitute $x=\sqrt{2}$ in (1).

$y=-5+2(\sqrt{2})^2$

$y=-5+4$

$y=-1$

Substitute $x=-\sqrt{2}$ in (1).

$y=-5+2(-\sqrt{2})^2$

$y=-5+4$

$y=-1$

Therefore the solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Option C is the correct answer.

6 0

2 years ago