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2 years ago

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Mathematics

1 answer:

Alisiya [41]2 years ago

7 0

Answer:

f456897

Step-by-step explanation:

because we dont like it

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(a) Complete the table of values for y- 2x + 5 - 0 1 2 1 5 Y

maxonik [38]

Answer:

Step-by-step explanation:

I think you meant y = -2x + 5.

x y = -2x + 5

0 5

1 -2(1) + 5 = 3

2 -2(2) + 5 = 1

Note that every time you increase x by 1, y decreases by 2.

5 0

1 year ago

Solve the equation for y y +5=-(x – 3)

goldenfox [79]

Answer:

y=-x-2

Step-by-step explanation:

y+5=-(x-3)

y+5=-x+3

y=-x+3-5

y=-x-2

6 0

1 year ago

Read 2 more answers

Mary can paint a house 12 hours. if Nancy helps, it takes them 2 hours. without help, how long would it take Nancy to complete t

Talja [164]

I would say it takes Nancy 10 hours

3 0

2 years ago

Which function models the area of a rectangle with side lengths of 2x - 4 units and x + 1 units?

aalyn [17]

Answer:

Area of rectangle, $f(x)=2x^2-2x-4$ .

Step-by-step explanation:

We are given with side lengths of a rectangle are (2x-4) units and (x+1) units. It is required to find the area of rectangle.

The area of a rectangle is equal to the product of its length and breadth. It is given by :

$A=L\times B$

Let us consider, L = (2x-4) units and B = (x+1) units

Plugging the side lengths in above formula:

$A=(2x-4)\times (x+1)$

$A=2x^2+2x-4x-4\\\\A=2x^2-2x-4$

So, the function that models the area of a rectangle is $f(x)=2x^2-2x-4$ .

5 0

2 years ago

State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should

Yuki888 [10]

Solving for Angles

$\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A$

* Do not forget to use the inverse function towards the end, or elce you will throw your answer off!

Solving for Edges

$\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2$

You would use this law under two conditions:

One angle and two edges defined, while trying to solve for the third edge
ALL three edges defined

* Just make sure to use the inverse function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under three conditions:

Two angles and one edge defined, while trying to solve for the second edge
One angle and two edges defined, while trying to solve for the second angle
ALL three angles defined [of which does not occur very often, but it all refers back to the first bullet]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0

1 year ago