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2 years ago

Classify the following as elements, compounds and mixtures

Chemistry

1 answer:

9966 [12]2 years ago

7 0

Answer:

Elements

Gold, copper

Compounds

Sodium chloride, Sulphur dioxide, Aluminium oxide,

Mixture

Brass, rainwater, distilled water, sugar solution,muddy water

Explanation:

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What is the ph of a 0.014 M HCL solution?

Allushta [10]

Answer:

pH $= 1.853$

Explanation:

For every mole of hydrochloric acid, one mole of hydronium ion is required. Thus, in order to neutralize 0.014 moles of HCL, 0.014 moles of hydronium is required.

$[H_3O^+] = [HCl] = 0.014$

pH $= -log [H^+] = -log [H_3O^+]$

Substituting the available values in above equation, we can say that the pH of the solution is equal to

$- log (0.014)$

pH $= 1.853$

pH of a $0.014$ M HCL solution $= 1.853$

8 0

2 years ago

Match the function to the part of the cell.

Arada [10]

Lysosome is B. breaks down waste materials

Vacuole is A. temporary storage

Chloroplast is C. converts energy

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2 years ago

Scientists can tell recycling reduces atmospheric emissions by knowing which of the following? o it takes more Btu to manufactur

Dmitriy789 [7]

Answer:

According to the Environmental Paper Network's Paper Calculator, it takes about 32 million BTUs of energy to produce 1 ton of virgin paper fiber. To produce 1 ton of recycled paper, it takes about 22 million BTUs.

so the answer could be it takes less Btu to manufacture recycled products than new ones

7 0

2 years ago

Based on the following chemical equation how many hydrogen atoms are present in the products side?

e-lub [12.9K]

Answer:

the answer is 6

Explanation:

there is 3 hydrogen molecules in NH3 and there's 2 molecules of NH3 so in total, there are 6 hydrogen molecules on the products side.

8 0

2 years ago

what volume of a 0.155 M calcium hydroxide solution is required to neutralize 28.8 mL of a 0.106 M nitric acid?

Hitman42 [59]

Answer:

9.85mL

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

Ca(OH)2 + 2HNO3 —> Ca(NO3)2 + 2H2O

From the balanced equation above,

nA (mole of the acid) = 2

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of the base) =?

Mb (Molarity of base) = 0.155 M

Va (volume of the acid) = 28.8 mL

Ma (Molarity of acid) = 0.106 M

Using MaVa/MbVb = nA/nB, the volume of calcium hydroxide (i.e the base) can be obtain as follow:

MaVa/MbVb = nA/nB

0.106 x 28.8 / 0.155 x Vb = 2/1

Cross multiply to express in linear form as shown below:

2 x 0.155 x Vb = 0.106 x 28.8

Divide both side by 2 x 0.155

Vb = (0.106 x 28.8) / (2 x 0.155)

Vb = 9.85mL

Therefore, the Volume of calcium hydroxide is 9.85mL

7 0

2 years ago