Line k contains the points (-4,0) and (3,2). line m contains the points (-3,2) and (4,0). if line k is written in the form y=m1x
+b1 and line m is written in the form y=m2x+b2, what is the value of m1b2+m2b1?
what are the steps for solving this please?
1 answer:
Answer:
0
Step-by-step explanation:
(-4,0) and (3,2)
m1=(2-0)/(3+4)=2/7
y=2/7x+b1, using point (-4,0) to find b1 (substitute x=-4 and y=0 in the form)
0=2/7*(-4)+b1 ⇒ b1= 8/7
-----
(-3,2) and (4,0)
m2=(0-2)/(4+3)= -2/7
y= -2/7x+b2, using point (4,0) to find b2 (substitute x=4 and y=0 in the form)
0= -2/7*4+b2 ⇒ b2=8/7
----
m1b2+m2b1= 2/7*8/7 -2/7*8/7=0
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