1/6 = 2/12 because 12 is 2 times 6.
Multiply both numbers by 2 to get your answer:
5/6 = 10/12
Answer:
p = 0.07
p-hat = 0.035
p0 = 0.07
p-value = 0.003
Step-by-step explanation:
p = population parameter, in this case, the rate of infestations across all trees in the forest
p-hat = test statistic, in this case, the rate of infestations found in the sample of trees, i.e. those in Doug's backyard
p0 = the null hypothesis, in this case, the rate of infestations within the forest is correctly evaluated at 0.07 or 7%
p-value = the likelihood any difference between p and p-hat is down to chance
In this case 0.003 as the p-value means there is only 0.3% probability of our statistic value of 0.035 being down to variability and chance meaning it is 99.7% likely that there is some reason behind this difference;
We would accept the alternative hypothesis which says the current parameter value, 0.07, is in fact incorrect (either too high or too low, in this case, likely too high).
If i understood it right when you estimate the quotient it help you have an idea
1/2 : 1
2 : 4
3 : 6
Notice that every ratio consists of a number and double the number.
For 1/2 cup lemon juice, use 1 cup sugar.
The amount of sugar is twice the amount of lemon juice.
The ratio is 1:2
Since you are told the ratio is 1:r, that means r is 2.
The unit rate is 2 cups sugar per cup of lemon juice.
Answer:
Part a) The area of the swimming pool is
Part b) The total area of the swimming pool and the playground is
Step-by-step explanation:
Part a) Find the area of the swimming pool
we know that
The area of the swimming pool is
where
L is the length side
W is the width side
we have
substitute the values
therefore
The area of the swimming pool is
Part b) The area of the playground is one and a half times that of the swimming pool. Find the total area of the swimming pool and the playground
we know that
To obtain the area of the playground multiply the area of the swimming pool by one and a half
To obtain the total area of the swimming pool and the playground, adds the area of the swimming pool and the area of the playground
so
therefore
The total area of the swimming pool and the playground is