Hey there!
![\left[\begin{array}{ccc}\boxed{\boxed{ \frac{6}{4}}} \end{array}\right] = \left[\begin{array}{ccc}\boxed{\boxed{150}}\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%5Cboxed%7B%20%5Cfrac%7B6%7D%7B4%7D%7D%7D%20%5Cend%7Barray%7D%5Cright%5D%20%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%5Cboxed%7B150%7D%7D%5Cend%7Barray%7D%5Cright%5D%20)
All I did was to multiply each side by 100 which then go me this!
Hope this helps!
GM, because when naming a line, you go from left to right just like how we read.
Answer: The gradient of the line passing through is 3, thus the equation of the line becomes y=3x-4.
Step-by-step explanation: The parallel lines gradients that have similar gradients, so now we have the gradient of 3 because its similar to the other gradient. To get the equation of the line we use this equation: y=mx+c, we have to substitute the x and y to get the constant c.
5=3(3)+c
c= -4
y=3x+c
Answer: 66.50+5g= 83.50
g=3.4
Step-by-step explanation:
I think it is B, since x goes right 4.5 times and y goes up 3 times.
