Answer:
46 with a remainder of .5
Answer:
I'd say d but if you worry choose to be then go with B
Answer:
The correct option is B. The area of the figure is 40.4 units².
Step-by-step explanation:
The line AB divides the figure in two parts one is a rectangle and another is semicircle.
The distance formula is
The length of AB is
The length of AD is
Since AB=AD, therefore ABCD is a square. The area of the of square is
The area of square is 29 units².
The area of a semicircle is
Since AB is the diameter of the semicircle, therefore the radius of the semicircle is
The area of the semicircle is
The area of the figure is
Therefore the area of the figure is 40.4 units². Option B is correct.
Step-by-step explanation:
0.92×10^3
I think it helps you
Answer:
Dimensions of the rectangular plot will be 500 ft by 750 ft.
Step-by-step explanation:
Let the length of the rectangular plot = x ft.
and the width of the plot = y ft.
Cost to fence the length at the cost $3.00 per feet = 3x
Cost to fence the width of the cost $2.00 per feet = 2y
Total cost to fence all sides of rectangular plot = 2(3x + 2y)
2(3x + 2y) = 6,000
3x + 2y = 3,000 ----------(1)
3x + 2y = 3000
2y = 3000 - 3x
y =
y = 1500 -
Now area of the rectangle A = xy square feet
A = x[]
For maximum area
A' = = 0
1500 - 3x = 0
3x = 1500
x = 500 ft
From equation (1),
y = 1500 -
y = 1500 - 750
y = 750 ft
Therefore, for the maximum area of the rectangular plot will be 500 ft × 750 ft.
two fencing 3(500+500) = $3000
other two fencing 2(750+750) = $3000