Answer:
For this angular momentum, no quantum number exist
Explanation:
From the question we are told that
The magnitude of the angular momentum is 
The generally formula for Orbital angular momentum is mathematically represented as
Where 
is the quantum number
now
We can look at the given angular momentum in this form as
comparing this equation to the generally equation for Orbital angular momentum
We see that there is no quantum number that would satisfy this equation
Answer:
The temperature is 69.05 K.
Explanation:
We have,
Number of moles are 6
Pressure is 3.4 atm and a volume of 10 liters.
It is required to find the temperature. It can be calculated using gas law equation. It says that,
P is pressure
V is volume
n is number of moles
R is gas constant, 
T is temperature
Plugging all the values we get :
So, the temperature is 69.05 K.
B ............ is the answer,
D. precision. At first glance you can mark out A and B because the answers does not relate to the question. If question had said "what do you call it when the measurement is close to the actual answer" then you would have picked C. So that leaves you D. precision.
Answer:125.0964g
Explanation:
Density = mass/volume
Density = 2.7 gcm-3
Volume=2.7*1.2*14.3=46.332
Mass=?
Mass= density* volume
= 2.7× 46.332=125.0964g
