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2 years ago

If ey/n + k = t, what is y in terms of e, n, k, and t?

Mathematics

1 answer:

son4ous [18]2 years ago

3 0

So your goal is to set it equal to Y, so you have to start by subtracting k and you get t-k, then you have to get rid of the fraction by multiplying both sides by the denominator (n), so then you get n(t-k) and the only thing left is to divide by the e, and you get 4

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How many solutions does the equation 2(3x – 1) = 6x – 2 have?

netineya [11]

Answer:

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Step-by-step explanation:

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2 years ago

How many solutions does the equation<br> 3(2.4x + 4) = 4.1x + 7 + 3.1x have? Explain.

VMariaS [17]

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Step-by-step explanation:

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2 years ago

Need help I don’t know how to do it

liberstina [14]

First attempt to break the top portion up so the negative signs don’t confuse you.

(2 x -2) x (-2 x -4)/ 2 x 2

= (-4) x (8)/ 4

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1 year ago

Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id

Thepotemich [5.8K]

$\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

Explanation

$\frac{1}{a+bi}=c+di$

Step 1

multiplicate by the conjugate

$\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}$

notice that

$\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\ \end{gathered}$ $\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

I hope this helsp you

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Brut [27]

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Step-by-step explanation:

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