We have to write
In log form
To convert exponential equation to log equation, we have to use the following rule
So we will get
or
And that's the required log form .
Answer:
c. g(x) = 4x^2
Step-by-step explanation:
From a first glance, since g(x), is skinnier than f(x), meaning that it is increasing faster, so I know that I can eliminate options A & B since the coefficient on x needs to be greater than 1.
We can then look and see that g(1) = 4 as shown by the point given to us on the graph.
To find the right answer we can find g(1) for options C & D and whichever one matches the point on the graph is our correct answer. e
Option C:
once we plug in 1 for x, our equation looks like
4(1)^2.
1^2 = 1, and 4(1) = 4,
so g(1) = 4. and our point is (1,4).
This is the same as the graph so this is the CORRECT answer.
If you want to double check, you can still find g(1) for option D and verify that it is the WRONG answer.
Option D:
once we plug in 1 for x, our equation looks like
16(1)^2
1^2 = 1, and 16(1) = 16,
so g(1) = 16. and our point is (1,16).
This is different than the graph so this is the WRONG answer.
Actually Welcome to the concept of Parallel lines.
We must first understand that, Parallel Lines always have a same Slope, hence the 'm' value in y=mx+c equation will same, here it is '1/2' in the above equation,
so the points here are (-6,-17)
==>
(y-(-17)) = m(x-(-6))
==>
here m = 1/2 ,hence
y+17 = 1/2(x+6)
==> y+17 = 1/2(x) + 3
==> y = 1/2(x) + 3 - 17
==> y = 1/2(x) - 14
hence the Option 4.) is the correct answer!!
-4p=3p+28
-4p+4p=3p+3p+28
-28=6p+28-28
p=-28/6
p=-4 2/3
The completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
<h3>How to factor the polynomial?</h3>
The expression is given as:
2x^2 + 4x + 3xy + 6y
Group the expression into two
[2x^2 + 4x] + [3xy + 6y]
Factor out each group
2x(x + 2) + 3y(x + 2)
Factor out x + 2
(2x + 3y)(x + 2)
Hence, the completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
Read more about factored expression at:
brainly.com/question/723406
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