Answer:
.
Step-by-step explanation:
Since repetition isn't allowed, there would be choices for the first donut, choices for the second donut, and choices for the third donut. If the order in which donuts are placed in the bag matters, there would be unique ways to choose a bag of these donuts.
In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type times.
For example, if a bag includes donut of type , , and , the count would include the following arrangements:
Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count by to find the actual number of donut combinations:
.
Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of objects from a set of distinct objects:
.
8.5
the tenth is the first digit behind the dot. 4 rounds down so the 5 stays a 5
Answer:
B. looks like the best answer that fits this question.
If i'm wrong then my fault.
Step-by-step explanation:
When looking at choice (B) you can see it started at a decreasing point but slowly growing. Exponential relations are images or equations that describe growth and they always have the same function. If you look at the other choices you see that they either increase but then decrease or they don't match the formula for (exponential relations).
That's as good as I can do I dont knw if this what ur teacher is looking for but I tried :/
Answer:
28
Step-by-step explanation:
(-1)(-7)(4)
(7)(4)
28
Answer:
Option (d) is correct.
The given polynomial is a prime polynomial.
Step-by-step explanation:
Given :
We have to factorize it completely.
Since , factorization is the process of reducing a given polynomial into a lower degree polynomial by taking common factors out into the simplest form.
Consider the given polynomial
Since the given polynomial do not have any term common in both terms .
So we cannot factorized it further.
So, the given polynomial is a prime polynomial.
Thus, Option (d) is correct.