Answer:
The principal investment required to get a total amount of $ 1,000,000.00 from compound interest at a rate of 6% per year compounded 12 times per year over 45 years is $ 67,659.17.
Step-by-step explanation:
Given
- Accrued Amount A = $1000000
- Interest rate r = 6% = 0.06
- Compounded monthly n = 12
To determine:
Using the formula
substituting A = 1000000, r = 0.06, t = 45, and n = 12
$
Therefore, the principal investment required to get a total amount of $ 1,000,000.00 from compound interest at a rate of 6% per year compounded 12 times per year over 45 years is $ 67,659.17.
Answer The line two origins are 6 and 5.1
Step-by-step explanation:
Hope this helps ^^
Answer is d. -5/3 because y2-y1 =x2-x1
To find the y-intercept, simply set the value of x equal to 0, and solve for y, or f(x).
f(x) = 0^2 - 3(0) - 40
f(x) = -40
<h3>The y-intercept is -40.</h3>
Because this is a 2nd degree polynomial, we cannot find the x-intercepts in one step, and must instead use one of a few different methods.
In this case, we're going to use the quadratic formula:
Plug in the values.
3 +/- √(-3^2 + 160) / 2
3 +/- √169 / 2
3 +/- 13 / 2
(3 + 13) / 2 = 16 / 2 = 8
(3 - 13) = -10 / 2 = -5
<h3>The x intercepts are 8, and -5.</h3>