Solve each equation by substitution
2 answers:
Answer:
(1, 7)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS Equality Properties <u>Algebra I</u>
Solving systems of equations using substitution/elimination Step-by-step explanation:
<u>Step 1: Define systems</u>
y = 3x + 4
y = 6x + 1
<u>Step 2: Solve for </u><em><u>x</u></em>
Substitute in <em>y</em>: 3x + 4 = 6x + 1 Subtract 3x on both sides: 4 = 3x + 1 Subtract 1 on both sides: 3 = 3x Divide 3 on both sides: 1 = x Rewrite: x = 1
<u>Step 3: Solve for </u><em><u>y</u></em>
Define original equation: y = 6x + 1 Substitute in <em>x</em>: y = 6(1) + 1 Multiply: y = 6 + 1 Add: y = 7
Answer:
<em>(1, 7) </em>
Step-by-step explanation:
y = 3x + 4
y = 6x + 1
6x + 1 = 3x + 4 ⇒ x = 1
y = 3(1) + 4 = 7
<em>(1, 7)</em>
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