Answer:
Step-by-step explanation:
This is an inverse proportion.
men = k / Time So first we need to find k
k = men * Time Substitute values
k = 15*80
k = 1200 Notice the units are man days.
Now what happens if we increase the number of men to 20? What happens to the number of days.
20 = 1200 / time Multiply both sides by time
20*time = 1200 Now divide by 20
time = 1200/20
Answer: time = 60 days
Answer:
BlueSky06
2, 4, 5, 5, 6, 6, 7, 7, 7, 8, 8, 9, 9, 10
I believe the closest possible answer to this question are these numbers. Normal distribution graph needs to have a good bell-shaped figure. Thank you for your question. Please don't hesitate to ask in Brainly your queri
Step-by-step explanation:
Answer:
g(-1 )=-1 and g(2)+g(1)=7
Step-by-step explanation:
If g(x) = x^3+x^2-x-2 find g(-1)
if we find g(-1)
we substitute all the x's in the function with -1
-1^3+-1^2-(-1)-2
-1^3 = -1
-1^2 = 1
-1+1+1-2
(two minuses make a plus)
-1+1 = 0
0+1 = 1
1-2 = -1
if x=-1, g(-1) is -1
g(2)+g(1)
substitute the x's in the function with 2 and 1 and add your results
2^3+2^2-2-2
2^3 = 8, 2^2 = 4
8+4-2-2
8+4= 12, 12-2 = 10, 10-2 = 8
g(2)=8
g(1) now
1^3 + 1^2-1-2
1^3=1, 1^2 = 1
1+1-1-2
1+1 = 2, 2-1 = 1, 1-2 = -1
g(3) = -1
g(2) (which equals 8) + g(3) (which equals -1) =
8+(-1) = 7
g(2)+g(3)=7
Answer:
About 99.7% of births would be expected to occur within 51 days of the mean pregnancy length
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Standard deviation = 17.
About what percentage of births would be expected to occur within 51 days of the mean pregnancy length?
51/17 = 3.
So, within 3 standard deviations of the mean.
About 99.7% of births would be expected to occur within 51 days of the mean pregnancy length
