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1 year ago

HELP THIS IS MY LAST QUESTION. PLEASE

Mathematics

1 answer:

Jlenok [28]1 year ago

4 0

Answer:

Step-by-step explanation:

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Can sombody please help me with this math problem?

Molodets [167]

y=2/3y-3

1. y = 2/3 (9)-3 multiply 9 and 2 =18/3

y=18/3-3 divide 18 and 3 =6

y=6-3 subt. 3

y=3

2. -11=2/3x - 3

-11+3 = 2/3 x add 3 to both sides to cancel -3

-8=2/3 x

(3/2)-8 = (2/3)3/2 x multiply both sides by reciprical of 2/3

-24/2 = x divide

-12=x

4 0

2 years ago

Solve for x, −2 (4x+4) −3x − 2 = 34 help needed, thanks!

Arada [10]

Hey there!

The answer to your question is $-2 \frac{3}{11}$

$-2(4x+4) - 3x -2= 34$ Write the equation

$-8x - 8 - 3x - 2 = 34$ Distribute -2

$-11x-10 = 34$ Combine like terms

$-11x = 24$ Add 10 to both sides

$-2 \frac{3}{11}$ Divide both sides by -11

Hope it helps and have a great day!

4 0

2 years ago

Suppose you discover that your growth fund, income fund, and money market fund return

Alik [6]

Answer:−3+3=−4

2+3−=15

4−3−=19

2 3

Step 1: Pair the equations to eliminate y because the y terms are already additive inverses

−3+3=−4

2+3−=15

4−3−=19

2 3 4

3 =11

6 −2=34

Step 2: Write the two new equations

as a system

Step 3: Substitute the value for x and z

into one of the original equations

3 =11

3 5 +2=11

5−3+3 −2 =−4

15+2=11

6 −2=34

5−3−6=−4

−3−1=−4

2=−4

=−2

= 45

x = 5

−3=−3

The solution (5, 1, -2)

Step-by-step explanation:

3 0

2 years ago

What does y equal ??!?!

garik1379 [7]

<h3>Answer: 658.3</h3>

==================================================

Explanation:

The adjacent complementary angle to that 28 degree angle is 62 degrees because 62+28 = 90.

If the reference angle is the upper acute angle 62 degrees, then the y is the opposite leg and the side 350 is the adjacent leg.

Use the tangent ratio

tan(angle) = opposite/adjacent

tan(62) = y/350

350*tan(62) = y

y = 350*tan(62)

y = 658.254262871217

y = 658.3

3 0

2 years ago

Read 2 more answers

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brilliants [131]

Answer:

(a) x=2, y=-1

(b) x=2, y=2

(c) $\displaystyle x=\frac{5}{2}, y=\frac{5}{4}$

(d) x=-2, y=-7

Step-by-step explanation:

Cramer's Rule

It's a predetermined sequence of steps to solve a system of equations. It's a preferred technique to be implemented in automatic digital solutions because it's easy to structure and generalize.

It uses the concept of determinants, as explained below. Suppose we have a 2x2 system of equations like:

$\displaystyle \left \{ {{ax+by=p} \atop {cx+dy=q}} \right.$

We call the determinant of the system

$\Delta=\begin{vmatrix}a &b \\c &d \end{vmatrix}$

We also define:

$\Delta_x=\begin{vmatrix}p &b \\q &d \end{vmatrix}$

And

$\Delta_y=\begin{vmatrix}a &p \\c &q \end{vmatrix}$

The solution for x and y is

$\displaystyle x=\frac{\Delta_x}{\Delta}$

$\displaystyle y=\frac{\Delta_y}{\Delta}$

(a) The system to solve is

$\displaystyle \left \{ {{x+y=1} \atop {x-2y=4}} \right.$

Calculating:

$\Delta=\begin{vmatrix}1 &1 \\1 &-2 \end{vmatrix}=-2-1=-3$

$\Delta_x=\begin{vmatrix}1 &1 \\4 &-2 \end{vmatrix}=-2-4=-6$

$\Delta_y=\begin{vmatrix}1 &1 \\1 &4 \end{vmatrix}=4-3=3$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{3}{-3}=-1$

The solution is x=2, y=-1

(b) The system to solve is

$\displaystyle \left \{ {{4x-y=6} \atop {x-y=0}} \right.$

Calculating:

$\Delta=\begin{vmatrix}4 &-1 \\1 &-1 \end{vmatrix}=-4+1=-3$

$\Delta_x=\begin{vmatrix}6 &-1 \\0 &-1 \end{vmatrix}=-6-0=-6$

$\Delta_y=\begin{vmatrix}4 &6 \\1 &0 \end{vmatrix}=0-6=-6$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-6}{-3}=2$

The solution is x=2, y=2

$\displaystyle \left \{ {{-x+2y=0} \atop {x+2y=5}} \right.$

Calculating:

$\Delta=\begin{vmatrix}-1 &2 \\1 &2 \end{vmatrix}=-2-2=-4$

$\Delta_x=\begin{vmatrix}0 &2 \\5 &2 \end{vmatrix}=0-10=-10$

$\Delta_y=\begin{vmatrix}-1 &0 \\1 &5 \end{vmatrix}=-5-0=-5$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-10}{-4}=\frac{5}{2}$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-5}{-4}=\frac{5}{4}$

The solution is

$\displaystyle x=\frac{5}{2}, y=\frac{5}{4}$

(d) The system to solve is

$\displaystyle \left \{ {{6x-y=-5} \atop {4x-2y=6}} \right.$

Calculating:

$\Delta=\begin{vmatrix}6 &-1 \\4 &-2 \end{vmatrix}=-12+4=-8$

$\Delta_x=\begin{vmatrix}-5 &-1 \\6 &-2 \end{vmatrix}=10+6=16$

$\Delta_y=\begin{vmatrix}6 &-5 \\4 &6 \end{vmatrix}=36+20=56$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{16}{-8}=-2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{56}{-8}=-7$

The solution is x=-2, y=-7

4 0

2 years ago