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2 years ago

What is the value of 5 2/3 +(-3 5/6)+(-2/3)?

Mathematics

1 answer:

algol [13]2 years ago

5 0

Answer: I got 2/9 but im not sure if its right

Step-by-step explanation:

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The solid below is made from cubes.<br> Find its volume.

natali 33 [55]

Answer:

I believe its 30 yards

Step-by-step explanation:

volume = 3×5×2 = 30

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2 years ago

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Evaluating an Expression

Anna35 [415]

Answer:

130

Step-by-step explanation:

18+(4x28)

=18+112

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2 years ago

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A rain barrel is full of water and used to water the garden. The rain barrel loses water at the rate 2.5 gallons of water per mi

soldier1979 [14.2K]

Answer: <span>y - 37.5 = 2.5 ( x - 7)

Explanation:

1) The point-slope form is has this form:

y - y1 = m (x - x1)

Where m is the slope or rate of change and x1, y1 are the coordinates of the point.

2) you are told that the the rate of change of water (m) is 2.5

m = 2.5

3) The point is given by that after 7 min the rain barrel contains 37.5 gallons. This is:

x1 = 7
y1 = 37.5

</span>4) Replace those value in the point-slope model:

y - 37.5 = 2.5 ( x - 7)

That is the point-slope model or equation.

4 0

2 years ago

The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female consumers differ in the amo

Aloiza [94]

Answer:

$a)\ \ \bar x_m-\bar x_f=67.03\\\\b)\ \ E=15.7416\\\\c)\ \ CI=[51.2884, \ 82.7716]$

Step-by-step explanation:

a. -Given that:

$n_m=41\ , \ \sigma_m=33, \bar x_m=135.67\\\\n_f=37. \ \ ,\sigma_f=20, \ \ \bar x_f=68.64$

#The point estimator of the difference between the population mean expenditure for males and the population mean expenditure for females is calculated as:

$\bar x_m-\bar x_f\\\\\therefore \bigtriangleup\bar x=135.67-68.64\\\\=67.03$

Hence, the pointer is estimator 67.03

b. The standard error of the point estimator, $\bar x_m-\bar x_f$ is calculated by the following following:

$\sigma_{\bar x_m-\bar x_f}=\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}$

-And the margin of error, E at a 99% confidence can be calculated as:

$E=z_{\alpha/2}\times \sigma_{\bar x_m-\bar x_f}\\\\\\=z_{0.005}\times\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\\\=2.575\times \sqrt{\frac{33^2}{41}+\frac{20^2}{37}}\\\\\\=15.7416$

Hence, the margin of error is 15.7416

c. The estimator confidence interval is calculated using the following formula:

$\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}$

#We substitute to solve for the confidence interval using the standard deviation and sample size values in a above:

$CI=\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\=(135.67-68.64)\pm 15.7416\\\\=67.03\pm 15.7416\\\\=[51.2884, \ 82.7716]$

Hence, the 99% confidence interval is [51.2884,82.7716]

7 0

2 years ago

Please help me with this question... please

kolbaska11 [484]

Answer:

Step-by-step explanation:

3 0

2 years ago

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What is the value of 5 2/3 +(-3 5/6)+(-2/3)? ​

What is the value of 5 2/3 +(-3 5/6)+(-2/3)?