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2 years ago

Which of the following statements is consistent with the electron configuration 1s22s22p63s23p4?

Chemistry

1 answer:

spayn [35]2 years ago

6 0

Answer:

Explanation:

When finding the element based on its electronic configuration the subscripts gives the number of electrons in the element.

In the given example total number of subscripts are 16. This means the element has 16 electrons which is equal to the atomic number of the element. hence, the element is Sulphur.

Here, s, p, d, and f are orbitals. So, as per the EC given, 3p orbital has 4 electrons in it. Hence, option (a) is correct.

Since, s, p, d, and f are orbitals and not shells, subshells. Therefore, other options are incorrect.

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<u>Answer:</u> The net ionic equation for the given reaction is $2H^+(aq.)+SO_3^{2-}(aq.)\rightarrow H_2O(l)+SO_2(g)$

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are the ions which do not get involved in a chemical equation. It is also defined as the ions that are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of hydrochloric acid and potassium sulfite is given as:

$2HCl(aq.)+K_2SO_3(aq.)\rightarrow 2KCl(aq.)+SO_2(g)+H_2O(l)$

Ionic form of the above equation follows:

$2H^+(aq.)+2Cl^-(aq.)+2K^+(aq.)+SO_3^{2-}(aq.)\rightarrow 2K^+(aq.)+2Cl^-(aq.)+SO_2(g)+H_2O(l)$

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The net ionic equation for the above reaction follows:

$2H^+(aq.)+SO_3^{2-}(aq.)\rightarrow SO_2(g)+H_2O(l)$

Hence, the net ionic equation for the given reaction is written above.

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