Answer:
We need a sample size of at least 170.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population(square root of the variance) and n is the size of the sample.
How large of a sample would be required in order to estimate the mean per capita income at the 80%80% level of confidence with an error of at most $0.52$ 0.52?
A sample size of at least n, in which n is found when 
So
Rounding up
We need a sample size of at least 170.
im not sure this is right
g'(x) = 6b(-5x + 1)^5 (-5)
g'(x) = -30b(-5x +1)^5
g''(x) = -30b(5)(-5x + 1)^4 (-5)
g''(x) = 750b (-5x +1)^4
g(x) = b(−5x + 1)6 − a
when
g(-x) = b(5x +1)6 - a
g'(x) = -30b(-5x +1)^5 = 0
-5x +1 = 0
x = 15
Answer:
2x^7
Step-by-step explanation:
Multiply
x
^4 by x
^3 by adding the exponents.
Answer:
<h3>-16</h3>
Step-by-step explanation:
PEMDAS- (Parenthesis, Exponents, Multiply, Divide, Add, and Subtract) from left to right.
BOMDAS- (Brackets, Of, Multiply, Divide, Add, and Subtract) from left to right.
(-8)2
-8*2 (First, remove parenthesis.)
-8*2=-16
-16
Therefore, the final answer is -16.
The measure of angle QPR is 30 degrees
