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2 years ago

Can someone help me with this pls I don’t understand??

2 answers:

4 0

Slope intercept form is y = mx + b.

m is the slope and b is the variable for the y-intercept. All you have to do is to substitute the numbers to the corresponding variables.

So the answer would be: y = 2/7x + 0 or y = 2/7x

Lynna [10]2 years ago

4 0

Hello again! To do this you must remember that slope intercept form is y=mx+b. m equals slope while b equals y intercept. Our slope is 2/7 while our y intercept is zero. Now, plug them in and you should get the equation y=2/7x+0. We have a zero at the end so we remove the + and zero and get y=2/7x.

Hope it helps! If you need help in the future be sure to reach out to me!

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Simplify this please brainly if correct ! Thanks

MrRissso [65]

Answer:

$\frac{\sqrt{3} \sqrt{3} }{1} = 3$

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

ALGEBRA HELP PLZZZZZZZZZ

Elan Coil [88]

1st transformation:
$A'=(-3,-4)\\
B'=(-7,-4)\\
C'=(-3,-8)\\
D'=(-7,-8)$

2nd transformation:
When you rotate a point around the origin by 180 degrees, you change both coordinates to opposite values.
$A''=(3,4)\\ B''=(7,4)\\ C''=(3,8)\\ D''=(7,8)$

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2 years ago

What is the percent of 200 miles is 150

mixas84 [53]

The answer is 75% Proportions can help with this :)

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2 years ago

an airport charges an additional fee for a piece of luggage that weighs more than 50 lbs write an inequality that shows the weig

nekit [7.7K]

Answer:

X ≤ 50

Step-by-step explanation:

Since the additional fee for a piece of luggage is only charged if it weighs more than 50 lbs, than Michael's suitcase weight must be less than, or equal to, 50 lbs. Using 'X' as the weight of Michael's suitcase in pounds:

X ≤ 50

'X' is less than or equal to 50 lbs

4 0

2 years ago

Please help. 10 points. Please do not guess. Guesses will be reported.

Alex73 [517]

The inscribed angle theorem says that

$m\angle CAB=\dfrac12m\angle COB$

Triangle AOC is isosceles because both AO and CO are radii of the circle and have the same length. This means angles CAO and ACO have the same measure and are congruent.

Angles ACO and COD are congruent because they form an alternating interior pair between the parallel lines AC and OD.

Taking all these facts together, we have

$m\angle COB=2m\angle COD$

and since angle COB is made up of angles COD and DOB, these angles must be congruent, and so the arcs they subtend (CD and DB, respectively) must also congruent.

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2 years ago