All categories

2 years ago

Help please.........

Mathematics

1 answer:

Ksenya-84 [330]2 years ago

6 0

Answer: 36000

Step-by-step explanation:

try looking it up lol

You might be interested in

The number of users of a cell tower in a small, developing town increased by a factor of 1.5 every year from 2010 to 2019. The f

polet [3.4K]

Answer:

Step-by-step explanation:

From the statement, we are given a function that shows the number of cell tower users f(x) after x years, from the year 2010 to 2019, so, to solve the problem, we need to remember that the domain is equal to all the values that the variable (x for this case) could take making the function itself exist.

So, the given function is a function of years, and we know that "x" represents the years from 2010 (starting value), to 2019 (ending value) meaning that the domain is located between those two values.

Hence, the correct option is:

B. 0 ≤ x ≤ 5,000

3 0

2 years ago

Read 2 more answers

1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.

xxTIMURxx [149]

First, rewrite the equation so that y is a function of x :

$x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}$

(If you were to plot the actual curve, you would have both $y=x^{2/3}$ and $y=-x^{2/3}$ , but one curve is a reflection of the other, so the arc length for 1 ≤ x ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

$\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx$

We have

$y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}$

Then in the integral,

$\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx$

Substitute

$u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx$

This transforms the integral to

$\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du$

and computing it is trivial:

$\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)$

We can simplify this further to

$\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}$

7 0

2 years ago

What is the value of x? 5 sqrt 2 10 sqrt 2 5 10

vitfil [10]

Hey there! :D

So, basically, you could say that "x" is equal to both of the legs.

We also know that in 45-45-90 triangles, x*√2= the hypotenuse

Given this information, if we were to divide 10 by the √2, we would get:

10/√2= 7.071.....

5√2= 7.071....

5√2 is the answer.

I hope this helps!
~kaikers

6 0

2 years ago

Given:

ludmilkaskok [199]

Segment GZ and Segment XY

I hope that this helped you!

4 0

2 years ago

2/3[8(5-2)^{2}+3*2] How do I distribute the 2/3 and then solve the rest?

Dafna1 [17]

Before I distribute, I solve the inside first:

2/3[8(3)^2+6]

2/3[8(9)+6]

2/3[72+6]

2/3[78]

2*26= 52 is the answer

another way:

2/3[8(3)^2+6]

2/3[8(9)+6]

2/3[72+6]

(2/3)*72+(2/3)*6

2*24+2*2
48+4= 52

6 0

2 years ago