132/2 = 66
66/2 = 33
33/3 = 11
11/11 = 1
132 = 2^2 * 3 * 11
55121/11 = 5011
5011/5011 = 1
55,121 = 11 * 5011
LCM = common factor with larger exponent * not common factors
LCM = 2^2 * 3 * 11 * 5011
LCM = 661,452
Answer:
Range = 13
Mean = 8.3
Variance = 17.61
Step-by-step explanation:
Given the population dataset :
2, 9, 15, 4, 12, 9, 13, 6, 3, 10
1.) Range : (maximum - minimum)
Maximum = 15 ; minimum = 2
Range = (15 - 2) = 13
2.) population mean (μ) :
μ = ΣX / n
n = sample size
μ = (2 + 9 + 15 + 4 + 12 + 9 + 13 + 6 + 3 + 10) / 10
μ = 83 / 10
μ = 8.3
3.) Population variance (s²)
Σ(x - μ)² / n
=[(2 - 8.3)^2 + (9 - 8.3)^2 + (15 - 8.3)^2 + (4 - 8.3)^2 + (12 - 8.3)^2 + (9 - 8.3)^2 + (13 - 8.3)^2 + (6 - 8.3)^2 + (3 - 8.3)^2 + (10 - 8.3)^2] / 10
s² = 176.1 / 10
s² = 17.61
Answer:
I think it would be b
Step-by-step explanation:
im sorry if im wrong im not good with this stuff :c
D shows equivalent expressions