<u>Answer:</u>
The correct answer option is P (S∩LC) = 0.16.
<u>Step-by-step explanation:</u>
It is known that the probability if someone is a smoker is P(S)=0.29 and the probability that someone has lung cancer, given that they are also smoker is P(LC|S)=0.552.
So using the above information, we are to find the probability hat a random person is a smoker and has lung cancer P(S∩LC).
P (LC|S) = P (S∩LC) / P (S)
Substituting the given values to get:
0.552 = P(S∩LC) / 0.29
P (S∩LC) = 0.552 × 0.29 = 0.16
Answer:
The answer is 19
Step-by-step explanation:
I'm pretty sure the answer is 19
Firstly, the rate of increase of Canton = 80/7720 = 0.010
The rate of increase of HP = 120/3200 = 0.0375
Apply the formula of compound interest==> A =A'(1+i)^n
The population will be equal when the following equality is satisfied
7720(1+0.01)^n = 3200(1+0.0375)^n
or
7720x1.01^n = 3200x1.0375^n
Divide both sides by 3200 ===>(193/80)x1.01^n=1.0375^n
Answer:
C
Step-by-step explanation:
just round up to nearest number and 7/8 is 0.87 so it coloser to 1 than half and the others are way to big.