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2 years ago

Helppp ya boyyyyyy!!!!!!!!!

Mathematics

2 answers:

lawyer [7]2 years ago

8 0

The answer is definitely 866.84

Helen [10]2 years ago

3 0

Answer:

866.64

Step-by-step explanation:

40/2 = 20

A = πr²

3.14*20² = 1256

52/2 = 26

3.14*26² = 2122.64

2122.64 - 1256 = 866.64

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Simplify -8/2 divided by 6/-3

Alika [10]

<span><span>The answer would be 2
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</span></span><span>=<span>24/12
</span></span><span>=<span>24 ÷ 12/12 ÷ 12
</span></span><span>=<span>2

</span></span>

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2 years ago

What is the value of .3 the 4th power

MrMuchimi

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You earn $15.00 per hour at your job. If you get a 15% raise at the end of each year, what will your hourly rate, h, be after 6

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Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
The value of V(x) is p(1 - p)
The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

$E(x^2) = p$

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

Factor out p

$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

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2 years ago