The surface area of the sphere is:
A = 4 * pi * r ^ 2
Deriving we have:
A '= 8 * pi * r * r'
We clear the speed:
r '= A' / (8 * pi * r)
Substituting values:
r '= 24 / (8 * pi * 3)
r '= 1 / pi inch / sec
Then, the volume of the sphere is:
V = (4/3) * (pi) * (r ^ 3)
Deriving we have:
V '= (3) * (4/3) * (pi) * (r ^ 2) * (r')
Substituting values:
V '= (3) * (4/3) * (pi) * (3 ^ 2) * (1 / pi)
Rewriting:
V '= (4) * (9)
V '= 36 inch3 / sec
Answer:
the volume of the ice is changing at 36 inch3 / sec at that moment
Answer:
4/6 is the greater of the two.
Step-by-step explanation:
4/6 = 200/300
5/100 = 15/300
200/300 is visibly clear to be larger than 15/300.
The answer to the problem is C 2^12 the reason is because 16^3 is 4,096 and
2^7=128
2^11=2,048
2^12=4,096 which is what we want so this is the answer
2^64=18,447,744,073,709,551,616 which is not even close to what we want at all
So the answer is C 2^12
<span>The biggest number of groups that can be formed is 6, because six is the greatest common factor of 12 and 42. There will be 2 coaches in each group because 6 x 2 = 12 and 7 players in each group because 7 x 6 = 42.</span>
Answer:
288 small fish.
Step-by-step explanation:
The first thing is to calculate the volume of the prism, which would be the area of the base (length by width) and that by the height, that is:
a = l * w * h
l = 6
w = 4
h = 4
Replacing
a = 6 * 4 * 4
a = 96 cubic feet
they tell us that per cubic foot there is room for 3 small fish, therefore:
96 * 3 = 288
Which means that there are 288 small fish.