Ask question

Ask question

All categories

2 years ago

7

A pool in the shape of a rectangular prism is being filled with water. The length and width of the pool is 24 feet and 15 feet.

If the height of the water in the pool is 113 feet, what is the volume of the water in cubic feet?

1 answer:

Marina86 [1]2 years ago

6 0

Answer:

40,680

Step-by-step explanation:

plz give me brainliest

remember your units

hope this help

You might be interested in

Choose the best decimal equivalent to 5/8

vlada-n [284]

To convert this fraction to a decimal, just divide the numerator (5) by the denominator (8): 5 ÷ 8 = 0.625. So,

5/8 = 0.625

Rounded values:

<span><span>5/8 = 1 rounded to the nearest integer</span><span>5/8 = 0.6 rounded to 1 decimal place</span><span>5/8 = 0.63 rounded to 2 decimal places</span></span>

5 0

2 years ago

Read 2 more answers

Please help me I really need help with this

Helga [31]

Answer:

The answer might be c

Step-by-step explanation:

4 0

2 years ago

Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.

Hitman42 [59]

$\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}
$

7 0

2 years ago

What are the domain and range for each of the following functions

coldgirl [10]

Answer:

a.) DomainL: -2 ≥ x < 1 Range: 1 ≥ y < 2

b.) DomainL: -2 > x < 2 Range: -2 > y < 2

Step-by-step explanation:

look up what the open and closed dots mean

understand how to determine values on the y or x axis

7 0

2 years ago

You are rearranging your bookshelf to make it more interesting and harder to find anything on it. On one of the shelves you plan

Leto [7]

Answer:

for every 2 biographies you put 1 mystery book until you get to the middle then there will be 3

Step-by-step explanation:

8 0

1 year ago