-3z + 7 = -7 - 10z
Add 10z to both sides
7z + 7 = -7
Subtract 7 from both sides
7z = -14
Divide by 7
Z = -2
The solution for this problem would be:
Given that there is 99.999%.
Let denote n as the network servers and p as the reliability of each server.
So the probability that the network uptime = 1 - (1 - p)^n
Therefore, (1-p) ^n = 0.00001
a. x= log(1-.99999)÷log(1-.97)= 3.2833 is the answer
1-(1-.97)^3= 0.99999 + 0.0001 = 1
b. x = log(1-.99999)÷log(1-.88) = 5.43 is the answer
1-(1-.88)^3= 0.99 + 0.0001 = approx 1
Answer:
1
Step-by-step explanation:
x is 1 and y is 1 and the total is three so 1