Answer: (a) e ^ -3x (b)e^-3x
Step-by-step explanation:
I suggest the equation is:
d/dx[integral (e^-3t) dt
First we integrate e^-3tdt
Integral(e ^ -3t dt) as shown in attachment and then we differentiate the result as shown in the attachment.
(b) to differentiate the integral let x = t, and substitute into the expression.
Therefore dx = dt
Hence, d/dx[integral (e ^-3x dx)] = e^-3x
Step-by-step explanation:
"product" means multiplication. the same as "times".
so,
135 = r×9
Quartile or interquartile.
Givens
Let the smallest integer = x
The middle integer = x + 1
The largest integer = x + 2
Remark
The first phrase up to is says the sum of ... The key word is sum. So far you have x + x + 1 + x + 2. Simplified this comes to 3x + 3.
Two times the 2nd number is 2*(x + 1) and from that, subtract 14
2(x + 1) - 14
If you break down each phrase as I have done you will soon become very good at doing these types of problems.
So the equation looks like this.
Solution
3x + 3 = 2(x + 1) - 14 Remove the brackets.
3x + 3 = 2x + 2 - 14 Combine the like terms on the right.
3x + 3 = 2x - 12 Subtract 3 from both sides.
3x = 2x - 12 - 3
3x = 2x - 15 Subtract 2x from both sides.
3x - 2x = - 15
x = -15 <<<< Answer for smallest number.
Answer
-15
- 14
-13 Are the three numbers you seek.
Answer:
10.8
Step-by-step explanation:
to so the mean you add up all of the numbers and divide by the amount you have. so add up all the numbers to get 54, the divide 54 by 5 because there are numbers.