Answer:
Natalie's age is 14
Sasha's age is 17
Step-by-step explanation:
Let
Sasha's age be "s", and
Natalie's age be "n"
<u>Sum of Sasha and Natalie is 31:</u>
s + n = 31
<u>Twice Natalie is 11 more than Sasha:</u>
2n = s + 11
We ca solve this equation for s first:
s = 2n - 11
We put this into first equation and solve for n first:
s + n = 31
2n - 11 + n = 31
3n = 31 + 11
3n = 42
n = 42/3 = 14
Natalie's age is 14
Also, s = 2n - 11
s = 2(14) - 11
s = 28 - 11
s = 17
Sasha's age is 17
For this case, the first thing we must do is define variables.
We have then:
x: Maggie's age
y: Age of Maggie's brother
We write the system of equations that models the problem.
We have then:
We solve the system of equations.
For this, we use substitution:
From here, we clear the value of x:
Answer:
Maggie is 9 years old
We have .
First let us factor the 2 to obtain,
We can now see clearly that the expression inside the parentheses is a difference of two squares.
We now write the 4 as 2². So that we obtain the expression,
Recall that
Hence our expression becomes,
Therefore, when factored completely,
All the place values of 12, 354.897 are as follows: 12 thousands, 3
hundred, 5 tens, 4 ones, 0.8 tenths .09 hundredths, .007 thousandths.
Im guessing the first answer