Answer:
True
Step-by-step explanation:
Both sides (right side and left side) of the equation are indeed equal.
I hope this helps!
There is some ambiguity here which could be removed by using parentheses. I'm going to assume that you actually meant:
x-3
h(x) = ---------------
(x^3-36x)
To determine the domain of this function, factor the denominator:
x^3 - 36x = x(x^2 - 36) = x(x-6)(x+6)
The given function h(x) is undefined when the denominator = 0, which happens at {-6, 0, 6}.
Thus, the domain is "the set of all real numbers not equal to -6, 0 or 6."
Symbolically, the domain is (-infinity, -6) ∪ (-6, 0) ∪ (0, 6) ∪ (6, +infinity).
The scale factor from A to B is 5/3 and the value of r is 33/5
<h3>The scale factor from A to B</h3>
From the figure, we have the following corresponding sides
A : B = 5 : 3
Express as fraction
B/A = 3/5
This means that, the scale factor from A to B is 5/3
<h3>The value of r</h3>
From the figure, we have the following corresponding sides
A : B = 11 : r
Express as fraction
B/A = r/11
Recall that:
B/A = 3/5
So, we have:
3/5 = r/11
Multiply by 11
r = 33/5
Hence, the value of r is 33/5
Read more about similar shapes at:
brainly.com/question/14285697
#SPJ1
9. 31 + 5 = 36
10. 16 - 4 = 12
12. 9
13. 44 + 34 = 78
14. 101 - 1 = 100
15. -539 ???
16. 15 ??
17. |-435| = 435
M<ABC = m<EBD = 36 (vertical angles)
78 - x + 36 + 3x - 10 = 180 (straight angle)
Now solve for x
78 - x + 36 + 3x - 10 = 180
2x + 68 = 180
- 68 -68 (subtract 68 on both sides)
2x = 58
x = 29
