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2 years ago

In the combustion of hydrocarbon, carbon monoxide is formed. What has occured?

2 answers:

6 0

An incomplete combustion happened in the combustion of a hydrocarbon where carbon monoxide is produced. It happens when there is not enough oxygen to combust the hydrocarbon. The opposite is the complete combustion where CO2 and H2O is formed.

allochka39001 [22]2 years ago

4 0

<u>Answer:</u> This is an incomplete combustion reaction.

<u>Explanation:</u>

Combustion reaction is defined as the reaction in which a hydrocarbon produces carbon dioxide gas and water molecule when reacted with oxygen gas. General equation for this reaction is:

$\text{Hydrocarbon}+O_2(g)\rightarrow CO_2(g)+H_2O(l)$

Incomplete combustion is also a reaction between oxygen and hydrocarbon in which the products obtained are carbon monoxide, water and carbon. This type of combustion happens when there is insufficient supply of oxygen gas. General equation for this reaction is:

$\text{Hydrocarbon}+O_2(g)\rightarrow CO(g)+H_2O(l)+C(s)$

Hence, the hydrocarbon is undergoing an incomplete combustion reaction.

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Which of the following statements best describes why a solution of 6.00 g of Ca(NO3)2?in 30.0 g of water has a greater boiling-p

sukhopar [10]

Boiling-point elevation is a colligative property.

That means, the the boiling-point elevation depends on the molar content (fraction) of solute.

The dependency is ΔTb = Kb*m

Where ΔTb is the elevation in the boiling point, kb is the boiling constant, and m is the molality.

A solution of 6.00 g of Ca(NO3) in 30.0 g of water has 4 times the molal concentration of a solution of 3.00 g of Ca(NO3)2 in 60.0 g of water.:

(6.00g/molar mass) / 0.030kg = 200 /molar mass
(3.00g/molar mass) / 0.060kg = 50/molar mass

=> 200 / 50 = 4.

Then, given the direct proportion of the elevation of the boiling point with the molal concentration, the solution of 6.00 g of CaNO3 in 30 g of water will exhibit a greater boiling point elevation.

Or, what is the same, the solution with higher molality will have the higher boiling point.

5 0

2 years ago

Part III.The two reactions involved in quantitatively determining the amount of iodate in solution are: IO3-(aq) 5 I-(aq) 6 H (a

slega [8]

Answer:

$\large \boxed{\math{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}$

Explanation:

The I₂ is the common substance in the two equations.

(1) IO₃⁻ + 5I⁻ + 6H⁺ ⟶ 3I₂ + 3H₂O

{2) I₂ + 2S₂O₃²⁻ ⟶ 2I⁻ + S₄O₆²⁻

From Equation (1), the molar ratio of iodate to iodine is

$\dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{3}{1}$

From Equation (2), the molar ratio of iodine to thiosulfate is

$\dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} = \dfrac{2}{1}$

Combining the two ratios, we get

$\text{Stoichiometric factor} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{IO}_{3}^{-}} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} \times \dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{2}{1} \times \dfrac{3}{1} = \mathbf{\dfrac{6}{1}}\\\\\text{The stoichiometric factor is $\large \boxed{\mathbf{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}$}$

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2 years ago

Do you think these fish are an example of natural selection among two populations of the same species

pshichka [43]

I don’t see any fish or anything

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2 years ago

A pound of margarine costs $1.39. What is the cost of a kilogram of margarine

den301095 [7]

Answer:

3.064 $

Solution:

First of all we will find the number of pounds contained by one Kg. Therefore, it is found that,

1 Kilogram = 2.20462 Pounds

Hence, as given,

1 Pound of Margarine costs = 1.39 Dollars

So,

2.20462 Pounds Margarine will cost = X Dollars

Solving for X,

X = (2.20462 Pounds × 1.39 Dollars) ÷ 1 Pound

X = 3.064 Dollars

8 0

2 years ago

What is an atomic number? An atomic mass?

mrs_skeptik [129]

Answer:

The atomic number is the number of the elements inside the periodic table and the mass is the weight or a number under the elements.

Explanation:

Correct me if I am wrong

4 0

2 years ago

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