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Answer: 0.332 < p < 0.490
Step-by-step explanation:
We know that the confidence interval for population proportion is given by :-
, where n= sample size
= sample proportion
z* = critical z-value.
As per given , we have
n= 258
Sample proportion of college students who own a car =
Critical z-value for 99% confidence interval is 2.576. (By z-table)
Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be :
Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490