All categories

2 years ago

Find the distance between (-1,4) and (-1,12)

Mathematics

2 answers:

lukranit [14]2 years ago

8 0

Answer:

8 units

Step-by-step explanation:

Since both are on the same place in terms of the x-axis, this makes it much easier. Just go from (-1,4) and move upwards upon the graph until your at (-1,12). You counted 8 units. *mic drop*

Lapatulllka [165]2 years ago

5 0

Answer:

Step-by-step explanation:

8 because $\sqrt{(-1+1)^{2}+{(12-4)^{2}}$ = sqrt(8^2), which equal 8

You might be interested in

19. Determine the number of five-letter code words that can be formed from the word mommy.

bija089 [108]

Answer:

20 unique words

Step-by-step explanation:

mommy is a 5 letter word. So initially we would think there are 5! = 120 words to spell from here. however, If we are looking for unique solutions, we need to consider that there are 3 m's. the multinomial theorem says that we should divide by each group of duplicates so 5!/(3!1!1!) = 5!/3! = 20 unique words

7 0

2 years ago

HELP ASAPP!!!Select the correct answer.

alex41 [277]

Answer:

B. r=C/2pi

Step-by-step explanation:

C=2piR

C/2pi=R

3 0

2 years ago

Read 2 more answers

Tell whether the indicated angles are adjacent.

Semenov [28]

Answer: 3 would be a adjacent angle

Step-by-step explanation:

They don’t overlap

4 0

2 years ago

What is the volume of the prism? ft3 5.6 cm cm 9 cm 7.8 cm

Doss [256]

Answer:

I can not answer this question because vital information is missing.

Step-by-step explanation:

Pleas add a picture. At this moment I can not answer this question because vital information is missing.

3 0

2 years ago

Solve each system of linear equations albebraically

ANEK [815]

Step-by-step explanation:

$1.\\\left\{\begin{array}{ccc}y=3x&(1)\\2y=6x&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\2(3x)=6x\\6x=6x\qquad\text{subtract}\ 6x\ \text{from both sides}\\6x-6x=6x-6x\\0=0\qquad\text{TRUE}\\\\Answer:\ \text{Infinitely many solutions}\\\\\left\{\begin{array}{ccc}y=3x\\x\in\mathbb{R}\end{array}\right$

$2.\\\left\{\begin{array}{ccc}y=2x+5&(1)\\y-2x=1&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\(2x+5)-2x=1\\2x+5-2x=1\qquad\text{combine like terms}\\(2x-2x)+5=1\\5=-1\qquad\text{FALSE}\\\\Answer:\ \text{No solution.}$

$3.\\\left\{\begin{array}{ccc}3x-2y=9\\-6x+4y=1&\text{divide both sides by 2}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}3x-2y=9\\-3x+2y=0.5\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad0=9.5\qquad\text{FALSE}\\\\Answer:\ \text{No solution.}$

5 0

2 years ago