All stars in a stellar cluster have roughly the same distance.
<h3>What coloration are celebrity clusters?</h3>
Open clusters have a tendency to be blue in color. They frequently include glowing gas and dust. The stars in an open cluster are young stars that all formed from the equal nebula. These warm blue stars are in an open cluster known as the Jewel Bo
<h3>Are stars in the identical cluster?</h3>
Though stellar associations are grouped in with megastar clusters, they're pretty a bit different. "Stellar associations are companies of tens to hundreds of stars that have similar a while and metallicities, and are moving in roughly the equal direction within the galaxy, but are no longer gravitationally bound," Geller said.
Learn more about star cluster here:
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brainly.com/question/20326847</h3><h3 /><h3>#SPJ4</h3>
Answer:(a) 2.40 (b) horizontal distance. (c) 0.630. (d) 6.50
Explanation:that's all is talking about a speed and distance and time right
Light can't reflect off them I think
The west constituent of their sequence needs to cancel out 58 mph crosswind. Subsequently a northwest direction is a 45-degree angle up to even with the destination. That is the third point out of the triangle and the right angle is at the destination. The top side is the west constituent of their flight the vertical side is their resultant travel and the hypotenuse is their definite distance flown. Since the 58 mph crosswind was negated by flying northwest, the distance from the beginning to the destination must be the same distance as the west component of their travel. The hypotenuse is square root of twice the side since it has 2 identical sides.
c = sqrt (58^2 + 58^2) = sqrt (6728) = 82.02
Alternative solution:
c = sqrt (2) * 58 = 1.414 * 58 = 82.02
Therefore, they have to fly 82.02 mph
Answer:
acceleration = 0.022 m/s^2
distance = 8.3 x 10^7 m
speed = 1.9 x 10 ^3 m/s
Explanation:
the parameters given are:
mass = 900kg
force = 20N
- from the formula force = mass x acceleration
acceleration = force / mass
acceleration = 20 / 900
acceleration = 0.022 m/s^2
- distance travelled in 1 day (86,400 seconds) = (1/2) x a x t^2
(1/2) x 0.022 x (86,400^2) = 8.3 x 10^7 m
- speed of the sun yatch (v) = a x t
0.22 x 86400 = 1.9 x 10 ^3 m/s
