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2 years ago

If I double the amount I stretch a spring, what happens to its EPE

Physics

1 answer:

Rasek [7]2 years ago

7 0

Quadruples. My Class just went over this in physics

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The displacement volume of an automobile engine is 167 in3. what is the displacement volume in liters?

forsale [732]

The displacement volume in liters is 2.74 liters.

<h3>What is displacement volume?</h3>

Displacement volume is the quantity of solvent that will be displaced by a specified quantity of a solid during dissolution.

It can also be defined as the volume displaced by the piston as it moves between top dead center and bottom dead center in a car engine.

<h3>Displacement volume in liters</h3>

1 liter = 61.02 in³

? = 167 in³

= 167/61.02

= 2.74 liters

Thus, the displacement volume in liters is 2.74 liters.

Learn more about displacement volume here: brainly.com/question/1945909

#SPJ1

4 0

7 months ago

Two resistors, R1 and R2, are

dlinn [17]

The reciprocal of the total resistance is equal to the sum of the reciprocals of the component resistances:

1/(120.7 Ω) = 1/<em>R₁</em> + 1/(221.0 Ω)

1/<em>R₁</em> = 1/(120.7 Ω) - 1/(221.0 Ω)

<em>R₁</em> = 1 / (1/(120.7 Ω) - 1/(221.0 Ω)) ≈ 265.9 Ω

3 0

2 years ago

What is the downward pull on an object due to gravity?

Strike441 [17]

Answer:

force of gravity

Explanation:

The force of gravity is that which draws the bodies towards the surface of the Earth.

The force of gravity brakes the objects that move up and accelerates those that move down. It causes a parabolic movement in what we throw upwards,

3 0

2 years ago

Read 2 more answers

It is found that the most probable speed of molecules in a gas at equilibrium temperature

kaheart [24]

Answer:

$\frac{T_2}{T_1} = 1$

Explanation:

The root mean square velocity of the gas at an equilibrium temperature is given by the following formula:

$v = \sqrt{\frac{3RT}{M} }$

where,

v = root mean square velocity of molecules:

R = Universal Gas Constant

T = Equilibrium Temperature

M = Molecular Mass of the Gas

Therefore,

For T = T₁ :

$v = \sqrt{\frac{3RT_1}{M} }$

For T = T₂ :

$v = \sqrt{\frac{3RT_2}{M} }$

Since both speeds are given to be equal. Therefore, comparing both equations, we get:

$\sqrt{\frac{3RT_1}{M} }=\sqrt{\frac{3RT_2}{M} }\\\\\frac{T_2}{T_1} = 1$

8 0

2 years ago

In the great shopping cart race, two students push on shopping carts. A having twice the mass of B, with the same force applied

fiasKO [112]

B. cart B

Explanation:

The acceleration of each cart is given by Newton's second law:

$F=ma$

$a=\frac{F}{m}$

where F is the force applied, a is the acceleration and m is the cart's mass.

The force F applied is the same for the two carts, however the mass of cart A (mA) is twice than the mass of cart B (mB), so we can rewrite the two accelerations:

$a_A = \frac{F}{m_A}=\frac{F}{2 m_B}$

$a_B = \frac{F}{m_B}$

we see that the acceleration of cart B is twice the acceleration of cart A, therefore cart B will move faster and will win the race.

7 0

2 years ago