Answer:
99.7%
Step-by-step explanation:
Given that mean (μ) = 394.3 ms and standard deviation (σ) = 84.6 ms.
The empirical rule states that for a normal distribution:
- 68% falls within one standard deviation (μ ± σ)
- 95% falls within two standard deviation (μ ± 2σ)
- 99.7% falls within three standard deviation (μ ± 3σ)
one standard deviation = 394.3 ± 84.6 = (309.7, 478.9). 68% falls within 309.7 and 478.9 ms
two standard deviation = 394.3 ± 2 × 84.6 = (225.1, 563.5). 95% falls within 225.1 and 563.5 ms
three standard deviation = 394.3 ± 3 × 84.6 = (140.5, 648.1). 99.7% falls within 140.5 and 648.1 ms
Answer:
a) 
b) The should sample at least 293 small claims.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so , which means that the answer of question a is z = 1.645.
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
(b) If the group wants their estimate to have a maximum error of $12, how many small claims should they sample?
They should sample at least n small claims, in which n is found when
. So
The should sample at least 293 small claims.
Each die has six numbers, the total number of possible combinations is 6 * 6 = 36
The combinations in which you can get a sum of 5 are: 1 &4, 2 & 3, 4 &1, 3 &2
There are 4 different combinations of getting a sum of 5.
The probability would be 4/36, which reduces to 1/9
Answer:
5 terms
Step-by-step explanation:
nth term of the sequence =n^2 + 20
an= n^2 + 20
1st term when n= 1
1^2 + 20= 20
2nd term n= 2
2^2 + 20=24
3rd term when n= 3
3^2 + 20= 29
4th term when n= 4
4^2 + 20= 36
5th term when n= 5
5^2 + 20 =45
6th term when n= 6
6^2 + 20=56
Hence, terms in the sequence are less than 50 are first 5 terms
Answer:
320
Step-by-step explanation:
(45*3.5)+(65*2.5)=320
