Answer:
133/143
Step-by-step explanation:
Let S be the sample space
Let E be the event of selecting three committee partners with at least one junior partner.
Partners in the law firm include:
Senior partners = 6
Junior partners = 7
Total partners = 13
n(S) = number of ways of selecting 3 partners from 13 = 13C3
n(S) = 13C3 = 13!/(10!3!) = (13x12x11)/(3x2x1) = 286
To get n(E) i.e least 1 junior partner in the selected committee, we may have:
(2 senior and 1 junior) or ( 1 senior and 2 junior) or (3 junior).
Therefore, the required number of way is given below:
= (6C2 x 7C1) + (6C1 x 7C2) + 7C3
= [(6x5)/2 x 7] + [6 x (7x6)/2] + [(7x6x5)/(3x2)]
= 105 + 126 + 35
n(E) = 266
Therefore, the probability P(E) that at least one of the junior partners is on the committee is given below:
P(E) = n(E) /n(S)
P(E) = 266/286
P(E) = 133/143
√45 + √125
= 3√5 + 5√5
= 8√5
Answer is C.
Hope it helps!
Answer:
C) ∠LMO = 50°
Step-by-step explanation:
When you add the degrees of all the angles in a triangle, you get 180, so...
180 = 60 + 70 + x
180 - 60 - 70 = x
x = 50
I only know (b) and 28 (c)
(b) Multiples of 120= 120,240,360,480,600
Multiples of 150= 150,300,450,600
Both numbers have 600 as their first common multiple so the ANSWER is 600
28. (a) Common factors of 24= 1,2,3,4,6,8,12,24
Common factors of 64= 1,2,4,8,16,32,64
8 is the only common factor for both 24 and 64 so 8 is the ANSWER
Answer:
-6 for both
Step-by-step explanation:
0-6/5-4=-6
-10-(-4)/-2-(-3)=-6
