Ask question

Ask question

All categories

2 years ago

11

4x + x - 3-9 + 4x = 6 ??

1 answer:

Nookie1986 [14]2 years ago

8 0

Answer:

$x=2$

Step-by-step explanation:

-------------------------

Given:

$4x+x-3-9+4x=6$

---------->>>>

Combine like terms.

$9x-12=6$

---------->>>>

Add 12 to both sides.

$9x=18$

---------->>>>

Divide both sides by 9.

$x=2$

-------------------------

Hope this is helpful.

You might be interested in

Shania bought a $1455 drum set on the installment plan. The installment agreement included a 15% down payment and 18 monthly pay

ahrayia [7]

Answer:

A

Step-by-step explanation:

3 0

1 year ago

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

2 years ago

Read 2 more answers

I suck at math I need help with it!

muminat

Answer:

ok, I can help. Where's the math problem ?

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Work out the area of the circle.

Lelechka [254]

Answer:

A=πr2=π·212≈1385.44236cm²

4 0

1 year ago

Solve for the variable: -11t + 23 = 56

Annette [7]

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

<span> 3*x+23-(56)=0 </span>

3 0

2 years ago