Answer:
(a). 72.9%.
(b). 13.6 hr.
Step-by-step explanation:
So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;
=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "
=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"
So, we will be making use of the Crawford learning curve model.
T(7) + 10 = T (17) = 30 min.
T(7) = T1(7)^b = 45.
T(17 ) = T1(17)^b = 30.
(T1) = 45/7^b = 30/17^b.
45/30 = 7^b/17^b = (7/17)^b.
1.5 = (0.41177)^b.
ln 1.5 = b ln 0.41177.
0.40547 = -0.8873 b.
b = - 0.45696.
=> 2^ -0.45696 = 0.7285.
= 72.9%.
(b). T1= 45/7^ - 045696 = 109.5 hr.
V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .
V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .
= 815.7 min .
= 13.595 hr.
Answer:
1. 5/6 ≥ 2/3
2. 1/5 ≤ 2/8
3. 9/10 ≥ 6/8
4. I can't see it's out of the pic
5. 7/8 ≥ 5/10
6. 2/5 ≥ 2/6
7. 1/3 ≤ 3/8
8. I can't see it's out of the pic.
9. 8/10 ≥ 3/4
10. 3/8 ≤ 11/12
11. 2/3 ≤ 10/12
12. Can't see :(
13. 3/8 ≤ 7/8
14. 2/4 = 4/8
15. 6/8 ≥ 8/12
16. Can't see
Step-by-step explanation: All you have to do is divide the numerator by the denominator to make it into a decimal. For instance....
5/6 = approximately 0.83
I hope this helps you! It took forever....
The GCF is 36 since 36 can go into 144 (:
x
Answer:
(5,-4) and (-5,6)
Step-by-step explanation:
Given:
Solve it. First, express y in terms of x from the second equation:
Substitute it into the first equation:
Apply zero product property:
So,
When 
then 
When 
then 
We get two solutions: (5,-4) and (-5,6)
i think the answer is -50 but im
not sure
