Determine the center and radius of the following circle equation: x^2+y^2-8x+6y-75=0 x 2 +y 2 −8x+6y−75=0 Center: \big(( , \big)
) Radius:
1 answer:
Answer:
Compare x^2 +y^2-8x-6y=75 with the general circle equation x^2+y^2 -2ax-2by+c=0
-2a =-8 And -2b=-6
a=4 b=3
c=-75
To find the radius use the equation
r^2=a^2+b^2-c
r^2=4^2+ 3^2-(-75)
r^2=25+75=100
r=10(radius is always positive)
Hence the center is (4,3) and radius 10
Step-by-step explanation:
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