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2 years ago

What is the slope line perpendicular to the equation 4x+3y=9

Mathematics

1 answer:

aleksandrvk [35]2 years ago

7 0

Answer:

m=3/4

Step-by-step explanation:

first, let's put the line 4x+3y=9 from standard form (ax+by=c) into slope-intercept form (y=mx+b)

we have the equation 4x+3y=9

subtract 4x from both sides

3y=-4x+9

divide by 3

y=-4/3x+3

perpendicular lines have slopes that are negative and reciprocal. If the slopes are multiplied together, the result is -1

so to find the slope of the line perpendicular to the line y=-4/3x+3, we can take the slope of y=-4/3x+3 (-4/3) multiply it by a variable (this is our unknown value), and have that set to -1

(m is the slope value)

-4/3m=-1

multiply by -3/4

m=3/4

therefore the slope of the perpendicular line is 3/4

hope this helps!! :)

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2 years ago

The distance on the map between Yappy city and Quiet city is 23 cm.

jekas [21]

The actual distance between Yappy city and Quiet city when it is 23 cm in map is 9.2 miles.

What is scaling ?

It is the technique to resize drawing with comparing to actual size of object which uses proportion or ratio. For example, Mapping of earth, drawing prototype of automobiles.

It is given that :

The distance on the map between Yappy city and Quiet city is 23 cm

and,

5cm = 2 miles

now, for 1 cm on map it is equal to 2/5 miles of actual distance.

Therefore to find the actual distance of 23 cm in map we simply multiply 23 with 2/5 :

actual distance :

2/5 x 23 = 9.2 miles

Therefore, the actual distance between Yappy city and Quiet city is 9.2 miles.