Answer:
See attachment
Step-by-step explanation:
We want to graph on the interval -10 to 10.
Let be the parent absolute value function.
We can easily graph , if we use translation.
When the parent function is shifted downwards by 12 units, we obtain the graph of .
The parent function is a v-shaped graph with vertex at the origin.
We shift the parent function down so that its vertex is now at (0,-12) to get the graph of .
See attachment for the graph of on the specified interval.
Answer:
i got 4 but idk if its roght srry give it an try
Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
Answer:
Step-by-step explanation:
1,8
5,7
2,3
C
because you just eliminate it